Binary Search, the Ulam game and Coding Theory
Binary search allows us to search for an entry in a sorted list in time. In this post, I shall talk about a more general version, where the answers to some of the queries used during the binary search may be false (which is the Ulam game) and how that is related to adaptive block codes in coding theory and how these ideas help us.
Much of this is based on David desJardin’s PhD thesis which gives a general solution to Ulam’s game. I am writing about it because I had heard of the Ulam game where only one lie is allowed from a friend and was surprised to see the same crop up when learning about coding theory. It is not a very difficult topic while also being an interesting extension of something well known, so I thought I could give an overview in a post such as this.
The Ulam Game
The game 20 questions is a specific formulation of the problem of searching for a marked element in an ordered list of elements, and is easily solved by binary search. The game itself is the following:
Alice thinks of a number between one and one million. Bob can ask up to 20 yes/no questions to Alice, each of which Alice answers truthfully. Bob wins if he can determine which number Alice had thought of by asking just the 20 questions.
Note that is , which is just more than a million. Bob always wins because he can do a simple binary search for the number which will give him the answer in steps. The questions in this case could be of the form:
 is the number greater than ? If the answer is no,
 is the number greater than ?
and so on, halving the range every time.
This process of questioning can be formalized in the following way  each question can be thought of as a subset of the positive integers below one million, and Alice’s answer is yes if her chosen number belongs to the set and 0 otherwise.
It is interesting to note that Alice need not decide on her number at the beginning  if all her answers are merely consistent with some number that she chooses at the end, Bob still wins.
A more interesting version (the Ulam game) was posed by Stanislaw Ulam in his autobiography.
Someone thinks of a number between one and one million (which is just less than ). Another person is allowed to ask up to twenty questions, to each of which the first person is supposed to answer only yes or no. Obviously the number can be guessed by asking first, “Is the numebr in the first half million?” then again reduce the reservoir of numbers in the next question by onehalf, and so on. Now suppose one were allowed to lie once or twice, then how many questions would one need to get the right answer? One clearly neeeds more than n questions for guessing one of objects because one does not knw when the lie was told. This problem is not solved in general.
When I first came across this problem via a friend, the question was to find some lower bound on the number of questions needed. One possible lower bound is
where all logarithms are to the base2. The reason is the following: let us perform binary search again. In the worst case, we will need questions before we get a contradiction. Then we need to find the questions to which the answers were wrong, and since there are total questions, we need at least steps to find such questions.
It turns out that the Ulam game is equivalent to the problem of showing the existence of adaptive block codes of certain parameters, and this will occupy us for the rest of this post.
Adaptive Block Codes
Coding theory deals with reliable communication across a noisy channel. Alice and Bob are communicating over a channel that corrupts some of what Alice sends, and the idea is that Alice encodes the data in such a way that Bob can correctly decode it given some reasonable assumptions about the level of noise in the channel.
We can possible classification of channels is into two categories  with feedback and without feedback. Coding without feedback depends only on the input and the transmitter is assumed to have no information about what is happening at the receiver. In the feedback case, the encoder is also assumed to have access to the information about whether the previously sent information was received in error or not, and can possibly use this information while sending the rest of the data. In our case, this information is assumed to reach the encoder immediately and noiselessly.
Block coding is a coding technique where the information to be sent is broken up into chunks. Each of these chunks is mapped to chunks of appropriately chosen transmitted bits so as to reduce probability of error. This is in contrast to convolutional codes where the data to be sent is encoded into the transmitted bits continuously (without breaking into chunks).
Claude Shannon in his landmark 1948 papers showed that associated with every channel there is a certain rate of communication called the capacity which characterizes it. He showed that codes exist that guarantee nearly errorfree communication at rates below channel capacity. He also showed in 1956 that feedback does not increase the theoretical capacity of the forward channeel. However, the use of feedback in coding can give us better encoding and decoding strategies, therefore the question of the existence of adaptive block codes is an interesting question.
Equivalence of the Ulam Game and the existence of Adaptive Block Codes problem
The proof of this equivalence is in the above mentioned PhD thesis. Instead of redoing the proof, let’s see why the equivalence intuitively makes sense.
Let us consider what we are actually doing when we say we want an adaptive block code to exist. The message to be sent has been mapped to a chunk of bits to be transmitted and these bits are transmitted onebyone. Once each bit is sent the transmitter receives a signal from the receiver informing whether the bit was in error or not. What we want is that after all the bits have been sent, the receiver must be able to figure out which message was sent. The relation with the Ulam game is now clear  think of the bits being sent as being the yes/no questions in the Ulam game and the response from the receiver being the received answer. If in Ulam’s game a number can be pinpointed using N questions, we can say that a message M among possibilities can also be obtained with certainty after the whole process is over. In both cases the number of errors/lies is assumed to be less than some number E.
The formal statement of the above is the following.
There exists a winning strategy for Ulam’s game with parameters N, E, M if and only if there exists an adaptive block code with the same parameters.
Here N is the number of questions in Ulam’s game and the number of transmitted bits in the block code, E is the number of lies in Ulam’s game and the number of errors during transmission and M is the number of possible numbers/messages.
Solving the Ulam Problem
Next, let’s quickly take a look at how to tackle the Ulam game.
First, state space is constructed using tuples of nonnegative integers, and a game is defined on it. The game starts with an (E+1)tuple of nonnegative integers, called . There is a translation operator T defined on the tuples that drops the first number in the tuple and retains the rest, taking an (E+1)tuple to an Etuple. Bob partitions into and such that
and
Alice can choose either one of or , her choice becomes and the process is repeated. Bob wins if and only if sum of elements of is 0 or 1, and a state for which Bob wins is called a winning Nstate. If is the (E+1)tuple
then this game is shown to be equivalent to Ulam’s game with parameters N, E, and M defined above.
Using this state space representation, certain states are shown to be winning Nstates (for suitable N) in the state space, which are called:

singlets: those tuples for which sum of all entries is 1.

doublets: those tuples for which sum of all entries is 2.

zeroerror states: these are states where E=0 (that is, there are no lies). Then the tuple and such a state is winning Nstate iff .

Fibonacci states: these are explicitly constructed states that are part of a winning sequence of states. A sequence of states is called a winning Nstate sequence if is winning (N+3n)state for all n.
The volume of an Nstate, defined as
is shown to be at most for winning Nstates. This is called the volume bound.
Winning Nstates that meet the volume bound are either singlets or can be shown not to be winning (N1)states and are therefore called borderline winning Nstates.
Another result called the translation bound shows that if s is winning Nstate, and sum of all entries in s is at least 3, then (the translation operator T acting on s) is a winning (N3)state.
A final result called the summation rule for states gives a condition on states s that can be shown to be winning Nstates based only on the knowledge that certain states c and d are winning Nstates.
We can prove certain states are winning Nstates using the above results, in the following way. We start with certain states from the four categories that are known to be Nwinning, and put them together using the summation rule to find a (N+1)winning state. This lets us form a binary tree, with the parent being an Nwinning state and the children being (N1) winning states.
All these results allow us to find winning states. There are also some results that allow us to do the opposite, that is show that some state is a losing state. This is easy if the state violates the volume bound or the translation bound, and in other cases we can show results of the following form: if a tree rooted at a particular state is of depth x then the volume of the state is less than v. Thus, in some cases, looking at a state we can predict how deep the subtree at that state is.
Of course, because all three of the starting problems are equivalent, each of the winning Nstates we find also gives us a solution to the Ulam problem and shows the existence of an adaptive block code with the same parameters. Killing three birds with one stone.
The rest of the thesis uses all of these results to computationally find optimal codes given the parameters N, E, M. Optimal in this case means that an adaptive block code ceases to exist if the value of M is increased by one. The thesis includes parameters for all optimal block codes upto , please check that out if you are interested.
As mentioned above, this whole post is based on David desJardin’s PhD thesis. Please look at it for further details.